Base | Representation |
---|---|
bin | 11001001010111011… |
… | …01100100101000010 |
3 | 1021212202221001201222 |
4 | 30211131230211002 |
5 | 210133420144100 |
6 | 10112531555042 |
7 | 655606242620 |
oct | 144535544502 |
9 | 37782831658 |
10 | 13513443650 |
11 | 5804a94253 |
12 | 275175ba82 |
13 | 1374882c05 |
14 | 922a20510 |
15 | 541573485 |
hex | 32576c942 |
13513443650 has 96 divisors (see below), whose sum is σ = 30532152960. Its totient is φ = 4343915520.
The previous prime is 13513443649. The next prime is 13513443673. The reversal of 13513443650 is 5634431531.
It is a super-2 number, since 2×135134436502 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a self number, because there is not a number n which added to its sum of digits gives 13513443650.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1596329 + ... + 1604771.
It is an arithmetic number, because the mean of its divisors is an integer number (318043260).
Almost surely, 213513443650 is an apocalyptic number.
13513443650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13513443650 is an abundant number, since it is smaller than the sum of its proper divisors (17018709310).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13513443650 is a wasteful number, since it uses less digits than its factorization.
13513443650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8748 (or 8743 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 35.
The spelling of 13513443650 in words is "thirteen billion, five hundred thirteen million, four hundred forty-three thousand, six hundred fifty".
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