Base | Representation |
---|---|
bin | 1100010100101111101101… |
… | …0111010011010010111110 |
3 | 1202222102022201020120022002 |
4 | 3011023323113103102332 |
5 | 3234003003233304100 |
6 | 44453011202022302 |
7 | 2565665053626434 |
oct | 305137327232276 |
9 | 52872281216262 |
10 | 13550544041150 |
11 | 4354831938426 |
12 | 162a229947992 |
13 | 773a704ab03c |
14 | 34bbc7d16d54 |
15 | 1877327c72d5 |
hex | c52fb5d34be |
13550544041150 has 48 divisors (see below), whose sum is σ = 27606828518640. Its totient is φ = 4925471577600.
The previous prime is 13550544041149. The next prime is 13550544041173. The reversal of 13550544041150 is 5114044505531.
It is a super-2 number, since 2×135505440411502 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 274834256 + ... + 274883555.
It is an arithmetic number, because the mean of its divisors is an integer number (575142260805).
Almost surely, 213550544041150 is an apocalyptic number.
13550544041150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13550544041150 is an abundant number, since it is smaller than the sum of its proper divisors (14056284477490).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13550544041150 is a wasteful number, since it uses less digits than its factorization.
13550544041150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 549717869 (or 549717864 counting only the distinct ones).
The product of its (nonzero) digits is 120000, while the sum is 38.
Adding to 13550544041150 its reverse (5114044505531), we get a palindrome (18664588546681).
The spelling of 13550544041150 in words is "thirteen trillion, five hundred fifty billion, five hundred forty-four million, forty-one thousand, one hundred fifty".
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