Base | Representation |
---|---|
bin | 10011101110010000000… |
… | …101110100101110000000 |
3 | 11210120100102112121022211 |
4 | 103232100011310232000 |
5 | 134201210012102000 |
6 | 2514344143311504 |
7 | 166630252066432 |
oct | 23562005645600 |
9 | 4716312477284 |
10 | 1355332144000 |
11 | 48287a730a1a |
12 | 19a809bab594 |
13 | 9aa65769653 |
14 | 4985411a652 |
15 | 253c697e7ba |
hex | 13b90174b80 |
1355332144000 has 64 divisors (see below), whose sum is σ = 3369694582800. Its totient is φ = 542132851200.
The previous prime is 1355332143973. The next prime is 1355332144007. The reversal of 1355332144000 is 4412335531.
It is a tau number, because it is divible by the number of its divisors (64).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1355332144007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42338130 + ... + 42370129.
Almost surely, 21355332144000 is an apocalyptic number.
1355332144000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1355332144000 is an abundant number, since it is smaller than the sum of its proper divisors (2014362438800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1355332144000 is an frugal number, since it uses more digits than its factorization.
1355332144000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84708288 (or 84708266 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 1355332144000 its reverse (4412335531), we get a palindrome (1359744479531).
The spelling of 1355332144000 in words is "one trillion, three hundred fifty-five billion, three hundred thirty-two million, one hundred forty-four thousand".
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