Base | Representation |
---|---|
bin | 111111011000111010… |
… | …1011100011010110000 |
3 | 111000100222000201102220 |
4 | 1332301311130122300 |
5 | 4212242124012230 |
6 | 142311450041040 |
7 | 12556240124541 |
oct | 1766165343260 |
9 | 430328021386 |
10 | 136127563440 |
11 | 52805508250 |
12 | 22470a19180 |
13 | cab551500b |
14 | 68352024c8 |
15 | 381ac97d10 |
hex | 1fb1d5c6b0 |
136127563440 has 80 divisors (see below), whose sum is σ = 460358678016. Its totient is φ = 33000620800.
The previous prime is 136127563423. The next prime is 136127563447. The reversal of 136127563440 is 44365721631.
It is a tau number, because it is divible by the number of its divisors (80).
It is a super-2 number, since 2×1361275634402 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 136127563392 and 136127563401.
It is not an unprimeable number, because it can be changed into a prime (136127563447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25779096 + ... + 25784375.
Almost surely, 2136127563440 is an apocalyptic number.
136127563440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
136127563440 is an abundant number, since it is smaller than the sum of its proper divisors (324231114576).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136127563440 is a wasteful number, since it uses less digits than its factorization.
136127563440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51563498 (or 51563492 counting only the distinct ones).
The product of its (nonzero) digits is 362880, while the sum is 42.
The spelling of 136127563440 in words is "one hundred thirty-six billion, one hundred twenty-seven million, five hundred sixty-three thousand, four hundred forty".
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