Base | Representation |
---|---|
bin | 1100101111000111101111… |
… | …1101111101100111111000 |
3 | 1211120201221001202011011120 |
4 | 3023301323331331213320 |
5 | 3313414010321210340 |
6 | 45441110525025240 |
7 | 2643506035302333 |
oct | 313617375754770 |
9 | 54521831664146 |
10 | 14003673225720 |
11 | 4509a19508522 |
12 | 16a20099b5220 |
13 | 7a7704c61ba9 |
14 | 365ad223d61a |
15 | 1944036264d0 |
hex | cbc7bf7d9f8 |
14003673225720 has 64 divisors (see below), whose sum is σ = 43837585758720. Its totient is φ = 3571951430784.
The previous prime is 14003673225709. The next prime is 14003673225733. The reversal of 14003673225720 is 2752237630041.
It is a super-2 number, since 2×140036732257202 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2536894564 + ... + 2536900083.
It is an arithmetic number, because the mean of its divisors is an integer number (684962277480).
Almost surely, 214003673225720 is an apocalyptic number.
14003673225720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14003673225720 is an abundant number, since it is smaller than the sum of its proper divisors (29833912533000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14003673225720 is a wasteful number, since it uses less digits than its factorization.
14003673225720 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5073794684 (or 5073794680 counting only the distinct ones).
The product of its (nonzero) digits is 423360, while the sum is 42.
The spelling of 14003673225720 in words is "fourteen trillion, three billion, six hundred seventy-three million, two hundred twenty-five thousand, seven hundred twenty".
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