14110031141300 has 144 divisors (see below), whose sum is σ = 31461400008192. Its totient is φ = 5489831894400.

The previous prime is 14110031141243. The next prime is 14110031141321. The reversal of 14110031141300 is 314113001141.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1028196239 + ... + 1028209961.

Almost surely, 2^{14110031141300} is an apocalyptic number.

14110031141300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14110031141300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15730700004096).

14110031141300 is an abundant number, since it is smaller than the sum of its proper divisors (17351368866892).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14110031141300 is a wasteful number, since it uses less digits than its factorization.

14110031141300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14758 (or 14751 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 14110031141300 its reverse (314113001141), we get a palindrome (14424144142441).

The spelling of 14110031141300 in words is "fourteen trillion, one hundred ten billion, thirty-one million, one hundred forty-one thousand, three hundred".