Base | Representation |
---|---|
bin | 10000110100100… |
… | …11001011010100 |
3 | 100211112020022010 |
4 | 20122103023110 |
5 | 242111041040 |
6 | 22000304220 |
7 | 3332301210 |
oct | 1032231324 |
9 | 324466263 |
10 | 141112020 |
11 | 72721605 |
12 | 3b312070 |
13 | 2330954a |
14 | 14a53940 |
15 | c5c5e80 |
hex | 86932d4 |
141112020 has 96 divisors (see below), whose sum is σ = 453600000. Its totient is φ = 32108544.
The previous prime is 141111991. The next prime is 141112033. The reversal of 141112020 is 20211141.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a junction number, because it is equal to n+sod(n) for n = 141111987 and 141112005.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 112356 + ... + 113604.
It is an arithmetic number, because the mean of its divisors is an integer number (4725000).
Almost surely, 2141112020 is an apocalyptic number.
141112020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 141112020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (226800000).
141112020 is an abundant number, since it is smaller than the sum of its proper divisors (312487980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141112020 is a wasteful number, since it uses less digits than its factorization.
141112020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1537 (or 1535 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 12.
The square root of 141112020 is about 11879.0580434646. The cubic root of 141112020 is about 520.6205855077.
Adding to 141112020 its reverse (20211141), we get a palindrome (161323161).
It can be divided in two parts, 1411 and 12020, that added together give a palindrome (13431).
The spelling of 141112020 in words is "one hundred forty-one million, one hundred twelve thousand, twenty".
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