Base | Representation |
---|---|
bin | 10100100010011000110… |
… | …100001111011000011010 |
3 | 11222220211211121001012220 |
4 | 110202120310033120122 |
5 | 141110332123320120 |
6 | 3000203121444510 |
7 | 203651440311516 |
oct | 24423064173032 |
9 | 4886754531186 |
10 | 1411313104410 |
11 | 4a4597500060 |
12 | 1a9631aa0736 |
13 | a3117669bb1 |
14 | 4c444d01146 |
15 | 26aa144ab40 |
hex | 14898d0f61a |
1411313104410 has 64 divisors (see below), whose sum is σ = 3705662217600. Its totient is φ = 341156148480.
The previous prime is 1411313104403. The next prime is 1411313104483. The reversal of 1411313104410 is 144013131141.
It is a super-3 number, since 3×14113131044103 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6011917 + ... + 6242256.
It is an arithmetic number, because the mean of its divisors is an integer number (57900972150).
Almost surely, 21411313104410 is an apocalyptic number.
1411313104410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1411313104410 is an abundant number, since it is smaller than the sum of its proper divisors (2294349113190).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1411313104410 is a wasteful number, since it uses less digits than its factorization.
1411313104410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12254543.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 1411313104410 its reverse (144013131141), we get a palindrome (1555326235551).
The spelling of 1411313104410 in words is "one trillion, four hundred eleven billion, three hundred thirteen million, one hundred four thousand, four hundred ten".
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