141132112342320 has 80 divisors (see below), whose sum is σ = 477283143566592. Its totient is φ = 34213845415680.

The previous prime is 141132112342271. The next prime is 141132112342363. The reversal of 141132112342320 is 23243211231141.

141132112342320 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-3 number, since 3×141132112342320³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26729564092 + ... + 26729569371.

Almost surely, 2^{141132112342320} is an apocalyptic number.

141132112342320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141132112342320 is an abundant number, since it is smaller than the sum of its proper divisors (336151031224272).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141132112342320 is a wasteful number, since it uses less digits than its factorization.

141132112342320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53459133490 (or 53459133484 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 141132112342320 its reverse (23243211231141), we get a palindrome (164375323573461).

The spelling of 141132112342320 in words is "one hundred forty-one trillion, one hundred thirty-two billion, one hundred twelve million, three hundred forty-two thousand, three hundred twenty".