Base | Representation |
---|---|
bin | 1101000001000001110101… |
… | …0101100111000000010000 |
3 | 1212200011000201111212212112 |
4 | 3100100131111213000100 |
5 | 3333434042221444240 |
6 | 50234310420244452 |
7 | 3004646634235040 |
oct | 320203525470020 |
9 | 55604021455775 |
10 | 14311323234320 |
11 | 4618441963482 |
12 | 1731769240728 |
13 | 7ca7239515b8 |
14 | 376959381720 |
15 | 19c40c6e9665 |
hex | d041d567010 |
14311323234320 has 80 divisors (see below), whose sum is σ = 38027712677760. Its totient is φ = 4906677153792.
The previous prime is 14311323234289. The next prime is 14311323234343. The reversal of 14311323234320 is 2343232311341.
It is a tau number, because it is divible by the number of its divisors (80).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 75689819 + ... + 75878661.
It is an arithmetic number, because the mean of its divisors is an integer number (475346408472).
Almost surely, 214311323234320 is an apocalyptic number.
14311323234320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14311323234320 is an abundant number, since it is smaller than the sum of its proper divisors (23716389443440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14311323234320 is a wasteful number, since it uses less digits than its factorization.
14311323234320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 324192 (or 324186 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 14311323234320 its reverse (2343232311341), we get a palindrome (16654555545661).
The spelling of 14311323234320 in words is "fourteen trillion, three hundred eleven billion, three hundred twenty-three million, two hundred thirty-four thousand, three hundred twenty".
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