1431241013440 has 112 divisors (see below), whose sum is σ = 3948377078592. Its totient is φ = 483989078016.

The previous prime is 1431241013417. The next prime is 1431241013459. The reversal of 1431241013440 is 443101421341.

It is a tau number, because it is divible by the number of its divisors (112).

It is a Harshad number since it is a multiple of its sum of digits (28).

It is a junction number, because it is equal to n+sod(n) for n = 1431241013399 and 1431241013408.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4212829 + ... + 4539868.

Almost surely, 2^{1431241013440} is an apocalyptic number.

1431241013440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1431241013440 is an abundant number, since it is smaller than the sum of its proper divisors (2517136065152).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1431241013440 is an equidigital number, since it uses as much as digits as its factorization.

1431241013440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8752794 (or 8752784 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1431241013440 its reverse (443101421341), we get a palindrome (1874342434781).

The spelling of 1431241013440 in words is "one trillion, four hundred thirty-one billion, two hundred forty-one million, thirteen thousand, four hundred forty".