Base | Representation |
---|---|
bin | 100000100111001111100111… |
… | …001110001111111100000000 |
3 | 200210212012000211101120220121 |
4 | 200213033213032033330000 |
5 | 122300011432400401422 |
6 | 1225020451402350024 |
7 | 42132533652464464 |
oct | 4047174716177400 |
9 | 623765024346817 |
10 | 143434312122112 |
11 | 41780171960530 |
12 | 14106644abb314 |
13 | 6205a4a41896b |
14 | 275c3873924a4 |
15 | 118b0c7acd8c7 |
hex | 8273e738ff00 |
143434312122112 has 72 divisors (see below), whose sum is σ = 317630201374080. Its totient is φ = 64092373601280.
The previous prime is 143434312122071. The next prime is 143434312122131. The reversal of 143434312122112 is 211221213434341.
143434312122112 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 431490468 + ... + 431822755.
It is an arithmetic number, because the mean of its divisors is an integer number (4411530574640).
Almost surely, 2143434312122112 is an apocalyptic number.
It is an amenable number.
143434312122112 is an abundant number, since it is smaller than the sum of its proper divisors (174195889251968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143434312122112 is an equidigital number, since it uses as much as digits as its factorization.
143434312122112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 863313309 (or 863313295 counting only the distinct ones).
The product of its digits is 27648, while the sum is 34.
Adding to 143434312122112 its reverse (211221213434341), we get a palindrome (354655525556453).
The spelling of 143434312122112 in words is "one hundred forty-three trillion, four hundred thirty-four billion, three hundred twelve million, one hundred twenty-two thousand, one hundred twelve".
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