Base | Representation |
---|---|
bin | 11011110100001010… |
… | …11100010100111110 |
3 | 1102112201100120100020 |
4 | 31322011130110332 |
5 | 221040341231430 |
6 | 10505445113010 |
7 | 1036025446344 |
oct | 157205342476 |
9 | 42481316306 |
10 | 14933148990 |
11 | 6373411951 |
12 | 2a890b8766 |
13 | 153ca40946 |
14 | a193c1994 |
15 | 5c600bb10 |
hex | 37a15c53e |
14933148990 has 32 divisors (see below), whose sum is σ = 37725851520. Its totient is φ = 3772584864.
The previous prime is 14933148961. The next prime is 14933148991. The reversal of 14933148990 is 9984133941.
14933148990 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14933148991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13098684 + ... + 13099823.
It is an arithmetic number, because the mean of its divisors is an integer number (1178932860).
Almost surely, 214933148990 is an apocalyptic number.
14933148990 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14933148990 is an abundant number, since it is smaller than the sum of its proper divisors (22792702530).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14933148990 is a wasteful number, since it uses less digits than its factorization.
14933148990 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26198536.
The product of its (nonzero) digits is 839808, while the sum is 51.
The spelling of 14933148990 in words is "fourteen billion, nine hundred thirty-three million, one hundred forty-eight thousand, nine hundred ninety".
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