Base | Representation |
---|---|
bin | 10110011000110000001… |
… | …110010001011000011110 |
3 | 12110001220020211010210222 |
4 | 112120300032101120132 |
5 | 200201124234331200 |
6 | 3134422400201342 |
7 | 216101111425304 |
oct | 26306016213036 |
9 | 5401806733728 |
10 | 1538407339550 |
11 | 543486923024 |
12 | 20a1a1609252 |
13 | b20c0532a23 |
14 | 546604d4274 |
15 | 2a03e131d85 |
hex | 1663039161e |
1538407339550 has 24 divisors (see below), whose sum is σ = 2960107918200. Its totient is φ = 594143523680.
The previous prime is 1538407339531. The next prime is 1538407339577. The reversal of 1538407339550 is 559337048351.
It is a happy number.
It is a super-4 number, since 4×15384073395504 (a number of 50 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1538407339492 and 1538407339501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 530483840 + ... + 530486739.
It is an arithmetic number, because the mean of its divisors is an integer number (123337829925).
Almost surely, 21538407339550 is an apocalyptic number.
1538407339550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1538407339550 is a deficient number, since it is larger than the sum of its proper divisors (1421700578650).
1538407339550 is a wasteful number, since it uses less digits than its factorization.
1538407339550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1060970620 (or 1060970615 counting only the distinct ones).
The product of its (nonzero) digits is 6804000, while the sum is 53.
The spelling of 1538407339550 in words is "one trillion, five hundred thirty-eight billion, four hundred seven million, three hundred thirty-nine thousand, five hundred fifty".
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