Base | Representation |
---|---|
bin | 1111100100000000111100… |
… | …1100000000101101000000 |
3 | 2020120211112012102220201220 |
4 | 3321000033030000231000 |
5 | 4220323124023422422 |
6 | 100220512023555040 |
7 | 3414154361351346 |
oct | 371001714005500 |
9 | 66524465386656 |
10 | 17111404514112 |
11 | 54a79a6833737 |
12 | 1b0437a8bba80 |
13 | 9717a1c5008c |
14 | 4322a6cb3996 |
15 | 1ea190bc1e5c |
hex | f900f300b40 |
17111404514112 has 28 divisors (see below), whose sum is σ = 45273924444096. Its totient is φ = 5703801504640.
The previous prime is 17111404514081. The next prime is 17111404514117. The reversal of 17111404514112 is 21141540411171.
It is a happy number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (17111404514117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44560949064 + ... + 44560949447.
Almost surely, 217111404514112 is an apocalyptic number.
17111404514112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
17111404514112 is an abundant number, since it is smaller than the sum of its proper divisors (28162519929984).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
17111404514112 is an equidigital number, since it uses as much as digits as its factorization.
17111404514112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89121898526 (or 89121898516 counting only the distinct ones).
The product of its (nonzero) digits is 4480, while the sum is 33.
Adding to 17111404514112 its reverse (21141540411171), we get a palindrome (38252944925283).
The spelling of 17111404514112 in words is "seventeen trillion, one hundred eleven billion, four hundred four million, five hundred fourteen thousand, one hundred twelve".
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