Base | Representation |
---|---|
bin | 11101000111000011110… |
… | …000110000011111111000 |
3 | 21002020111101120001121020 |
4 | 131013003300300133320 |
5 | 230233402144200240 |
6 | 4130554044142440 |
7 | 264345604362405 |
oct | 35070360603770 |
9 | 7066441501536 |
10 | 2000444131320 |
11 | 701424619268 |
12 | 283848837a20 |
13 | 116844587a7b |
14 | 6cb718612ac |
15 | 37081eac0d0 |
hex | 1d1c3c307f8 |
2000444131320 has 64 divisors (see below), whose sum is σ = 6014879579520. Its totient is φ = 532247574144.
The previous prime is 2000444131271. The next prime is 2000444131337. The reversal of 2000444131320 is 231314440002.
It is a super-4 number, since 4×20004441313204 (a number of 50 digits) contains 4444 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18762154 + ... + 18868473.
It is an arithmetic number, because the mean of its divisors is an integer number (93982493430).
Almost surely, 22000444131320 is an apocalyptic number.
2000444131320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2000444131320 is an abundant number, since it is smaller than the sum of its proper divisors (4014435448200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2000444131320 is a wasteful number, since it uses less digits than its factorization.
2000444131320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37631084 (or 37631080 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 2000444131320 its reverse (231314440002), we get a palindrome (2231758571322).
The spelling of 2000444131320 in words is "two trillion, four hundred forty-four million, one hundred thirty-one thousand, three hundred twenty".
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