Base | Representation |
---|---|
bin | 11101000111111000000… |
… | …110000011111000111000 |
3 | 21002022202120200001201220 |
4 | 131013320012003320320 |
5 | 230242201431143000 |
6 | 4131221130512040 |
7 | 264406425301263 |
oct | 35077006037070 |
9 | 7068676601656 |
10 | 2001322131000 |
11 | 701835194435 |
12 | 283a52895620 |
13 | 11695444a6ca |
14 | 6cc162d1cda |
15 | 370d40e01a0 |
hex | 1d1f8183e38 |
2001322131000 has 64 divisors (see below), whose sum is σ = 6244125058080. Its totient is φ = 533685900800.
The previous prime is 2001322130981. The next prime is 2001322131001. The reversal of 2001322131000 is 1312231002.
It is a super-2 number, since 2×20013221310002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001322131001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 333550689 + ... + 333556688.
Almost surely, 22001322131000 is an apocalyptic number.
2001322131000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2001322131000 is an abundant number, since it is smaller than the sum of its proper divisors (4242802927080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2001322131000 is a wasteful number, since it uses less digits than its factorization.
2001322131000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 667107401 (or 667107387 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 2001322131000 its reverse (1312231002), we get a palindrome (2002634362002).
The spelling of 2001322131000 in words is "two trillion, one billion, three hundred twenty-two million, one hundred thirty-one thousand".
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