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20021112111300 = 22352193512475809
BaseRepresentation
bin1001000110101100001110…
…10001101000000011000100
32121212222222201121212210220
410203112013101220003010
510111011214200030200
6110325323311544340
74134322552013526
oct443260721500304
977788881555726
1020021112111300
1164199a6923803
1222b4285b2b0b0
13b22ca11bcba1
144d3054115a16
1524abdd57b4a0
hex1235874680c4

20021112111300 has 72 divisors (see below), whose sum is σ = 60976580061600. Its totient is φ = 5057965163520.

The previous prime is 20021112111289. The next prime is 20021112111311. The reversal of 20021112111300 is 311121112002.

It is an interprime number because it is at equal distance from previous prime (20021112111289) and next prime (20021112111311).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 20021112111300.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1756232205 + ... + 1756243604.

It is an arithmetic number, because the mean of its divisors is an integer number (846896945300).

Almost surely, 220021112111300 is an apocalyptic number.

20021112111300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

20021112111300 is an abundant number, since it is smaller than the sum of its proper divisors (40955467950300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20021112111300 is a wasteful number, since it uses less digits than its factorization.

20021112111300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3512475845 (or 3512475838 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 20021112111300 its reverse (311121112002), we get a palindrome (20332233223302).

The spelling of 20021112111300 in words is "twenty trillion, twenty-one billion, one hundred twelve million, one hundred eleven thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 15 19 20 25 30 38 50 57 60 75 76 95 100 114 150 190 228 285 300 380 475 570 950 1140 1425 1900 2850 5700 3512475809 7024951618 10537427427 14049903236 17562379045 21074854854 35124758090 42149709708 52687137135 66737040371 70249516180 87811895225 105374274270 133474080742 175623790450 200211121113 210748548540 263435685675 266948161484 333685201855 351247580900 400422242226 526871371350 667370403710 800844484452 1001055605565 1053742742700 1334740807420 1668426009275 2002111211130 3336852018550 4004222422260 5005278027825 6673704037100 10010556055650 20021112111300