Base | Representation |
---|---|
bin | 11101001000101100011… |
… | …111011100110111000000 |
3 | 21002102000211210111121020 |
4 | 131020230133130313000 |
5 | 230301002001431422 |
6 | 4131444252225440 |
7 | 264440261261646 |
oct | 35105437346700 |
9 | 7072024714536 |
10 | 2002201202112 |
11 | 702146421591 |
12 | 28405916b280 |
13 | 116a645c6c27 |
14 | 6cc9ad61196 |
15 | 3713638595c |
hex | 1d22c7dcdc0 |
2002201202112 has 112 divisors (see below), whose sum is σ = 5518547865600. Its totient is φ = 639945722880.
The previous prime is 2002201202059. The next prime is 2002201202123. The reversal of 2002201202112 is 2112021022002.
It is a super-3 number, since 3×20022012021123 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2002201202091 and 2002201202100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 894312 + ... + 2191847.
It is an arithmetic number, because the mean of its divisors is an integer number (49272748800).
Almost surely, 22002201202112 is an apocalyptic number.
It is an amenable number.
2002201202112 is an abundant number, since it is smaller than the sum of its proper divisors (3516346663488).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2002201202112 is a wasteful number, since it uses less digits than its factorization.
2002201202112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3086314 (or 3086304 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 15.
Adding to 2002201202112 its reverse (2112021022002), we get a palindrome (4114222224114).
The spelling of 2002201202112 in words is "two trillion, two billion, two hundred one million, two hundred two thousand, one hundred twelve".
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