Base | Representation |
---|---|
bin | 1011101101100010010… |
… | …0110000101111110000 |
3 | 201020100010002011202210 |
4 | 2323120210300233300 |
5 | 11244030203323440 |
6 | 232233025212120 |
7 | 20351654606415 |
oct | 2733044605760 |
9 | 636303064683 |
10 | 201202011120 |
11 | 78369320a20 |
12 | 32bb2191040 |
13 | 15c86368b66 |
14 | 9a499b610c |
15 | 5378c5aa80 |
hex | 2ed8930bf0 |
201202011120 has 160 divisors (see below), whose sum is σ = 687166447104. Its totient is φ = 48293248000.
The previous prime is 201202011103. The next prime is 201202011163. The reversal of 201202011120 is 21110202102.
201202011120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a junction number, because it is equal to n+sod(n) for n = 201202011096 and 201202011105.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 110652 + ... + 643931.
Almost surely, 2201202011120 is an apocalyptic number.
201202011120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 201202011120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (343583223552).
201202011120 is an abundant number, since it is smaller than the sum of its proper divisors (485964435984).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201202011120 is a wasteful number, since it uses less digits than its factorization.
201202011120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 754711 (or 754705 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 12.
Adding to 201202011120 its reverse (21110202102), we get a palindrome (222312213222).
The spelling of 201202011120 in words is "two hundred one billion, two hundred two million, eleven thousand, one hundred twenty".
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