Base | Representation |
---|---|
bin | 110000010000000101000110… |
… | …011100110111101010010000 |
3 | 1000211101012020212110211221000 |
4 | 300100011012130313222100 |
5 | 210303332040100214300 |
6 | 2031200253352502000 |
7 | 62461516613141016 |
oct | 6020050634675220 |
9 | 1024335225424830 |
10 | 212211221101200 |
11 | 61687300a81802 |
12 | 1b973b586aa900 |
13 | 9154580959c89 |
14 | 3a59113aaa8b6 |
15 | 198017a5e9c00 |
hex | c10146737a90 |
212211221101200 has 120 divisors (see below), whose sum is σ = 755314753661600. Its totient is φ = 56589658957440.
The previous prime is 212211221101193. The next prime is 212211221101259. The reversal of 212211221101200 is 2101122112212.
212211221101200 is a `hidden beast` number, since 21 + 2 + 211 + 221 + 10 + 1 + 200 = 666.
It is a tau number, because it is divible by the number of its divisors (120).
It is a super-3 number, since 3×2122112211012003 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9824582770 + ... + 9824604369.
Almost surely, 2212211221101200 is an apocalyptic number.
212211221101200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
212211221101200 is an abundant number, since it is smaller than the sum of its proper divisors (543103532560400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
212211221101200 is a wasteful number, since it uses less digits than its factorization.
212211221101200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19649187166 (or 19649187149 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 18.
Adding to 212211221101200 its reverse (2101122112212), we get a palindrome (214312343213412).
It can be divided in two parts, 21221122 and 1101200, that added together give a palindrome (22322322).
The spelling of 212211221101200 in words is "two hundred twelve trillion, two hundred eleven billion, two hundred twenty-one million, one hundred one thousand, two hundred".
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