Base | Representation |
---|---|
bin | 11111000000110000110… |
… | …101111000101101111010 |
3 | 21112201210122022010121010 |
4 | 133000300311320231322 |
5 | 234404020020224010 |
6 | 4311005142254350 |
7 | 306653135260314 |
oct | 37006065705572 |
9 | 7481718263533 |
10 | 2131123211130 |
11 | 751893549081 |
12 | 2a5038a273b6 |
13 | 125c6c055774 |
14 | 7520b1ba7b4 |
15 | 3a67e75e620 |
hex | 1f030d78b7a |
2131123211130 has 64 divisors (see below), whose sum is σ = 5541503476608. Its totient is φ = 522431293440.
The previous prime is 2131123211123. The next prime is 2131123211131. The reversal of 2131123211130 is 311123211312.
It is a super-2 number, since 2×21311232111302 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2131123211097 and 2131123211106.
It is not an unprimeable number, because it can be changed into a prime (2131123211131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 48567291 + ... + 48611150.
It is an arithmetic number, because the mean of its divisors is an integer number (86585991822).
Almost surely, 22131123211130 is an apocalyptic number.
2131123211130 is an abundant number, since it is smaller than the sum of its proper divisors (3410380265478).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2131123211130 is a wasteful number, since it uses less digits than its factorization.
2131123211130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97178511.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 2131123211130 its reverse (311123211312), we get a palindrome (2442246422442).
The spelling of 2131123211130 in words is "two trillion, one hundred thirty-one billion, one hundred twenty-three million, two hundred eleven thousand, one hundred thirty".
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