Base | Representation |
---|---|
bin | 1000001111101001… |
… | …0110110100100010 |
3 | 12201020100210110200 |
4 | 2003322112310202 |
5 | 14013024104442 |
6 | 1003334410030 |
7 | 105562102563 |
oct | 20372266442 |
9 | 5636323420 |
10 | 2213113122 |
11 | a36276710 |
12 | 519200916 |
13 | 2936731bc |
14 | 16dcd216a |
15 | ce45c34c |
hex | 83e96d22 |
2213113122 has 96 divisors (see below), whose sum is σ = 5531423040. Its totient is φ = 632448000.
The previous prime is 2213113093. The next prime is 2213113139.
2213113122 is nontrivially palindromic in base 10.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a nude number because it is divisible by every one of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 2213113095 and 2213113104.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 905422 + ... + 907862.
It is an arithmetic number, because the mean of its divisors is an integer number (57618990).
Almost surely, 22213113122 is an apocalyptic number.
2213113122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 2213113122, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2765711520).
2213113122 is an abundant number, since it is smaller than the sum of its proper divisors (3318309918).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2213113122 is a wasteful number, since it uses less digits than its factorization.
2213113122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2720 (or 2717 counting only the distinct ones).
The product of its digits is 144, while the sum is 18.
The square root of 2213113122 is about 47043.7362674352. The cubic root of 2213113122 is about 1303.1703924495.
It can be divided in two parts, 22131 and 13122, that added together give a palindrome (35253).
The spelling of 2213113122 in words is "two billion, two hundred thirteen million, one hundred thirteen thousand, one hundred twenty-two".
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