Base | Representation |
---|---|
bin | 10101100001101001… |
… | …100011101001000000 |
3 | 2012122210102011111100 |
4 | 111201221203221000 |
5 | 334313424322240 |
6 | 14341254214400 |
7 | 1445523165303 |
oct | 254151435100 |
9 | 65583364440 |
10 | 23113120320 |
11 | 9890832434 |
12 | 4590654400 |
13 | 2244647874 |
14 | 1193936b3a |
15 | 904206e30 |
hex | 561a63a40 |
23113120320 has 84 divisors (see below), whose sum is σ = 79499513340. Its totient is φ = 6163497984.
The previous prime is 23113120319. The next prime is 23113120333. The reversal of 23113120320 is 2302131132.
23113120320 is a `hidden beast` number, since 2 + 31 + 1 + 312 + 0 + 320 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 5197833216 + 17915287104 = 72096^2 + 133848^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 23113120293 and 23113120302.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4009815 + ... + 4015574.
Almost surely, 223113120320 is an apocalyptic number.
23113120320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
23113120320 is an abundant number, since it is smaller than the sum of its proper divisors (56386393020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
23113120320 is a wasteful number, since it uses less digits than its factorization.
23113120320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8025412 (or 8025399 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 23113120320 its reverse (2302131132), we get a palindrome (25415251452).
The spelling of 23113120320 in words is "twenty-three billion, one hundred thirteen million, one hundred twenty thousand, three hundred twenty".
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