Base | Representation |
---|---|
bin | 100001101010010101101… |
… | …110100011001011010100 |
3 | 22012010210012012120021201 |
4 | 201222111232203023110 |
5 | 300344420312210030 |
6 | 4530401010322244 |
7 | 326060235042625 |
oct | 41522556431324 |
9 | 8163705176251 |
10 | 2313204413140 |
11 | 81202a64a115 |
12 | 314393589384 |
13 | 13a198c0589a |
14 | 7dd6156ba4c |
15 | 40289a1a2ca |
hex | 21a95ba32d4 |
2313204413140 has 24 divisors (see below), whose sum is σ = 4940063664480. Its totient is φ = 909599023008.
The previous prime is 2313204413111. The next prime is 2313204413189. The reversal of 2313204413140 is 413144023132.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 2313204413099 and 2313204413108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 980170182 + ... + 980172541.
It is an arithmetic number, because the mean of its divisors is an integer number (205835986020).
Almost surely, 22313204413140 is an apocalyptic number.
2313204413140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2313204413140 is an abundant number, since it is smaller than the sum of its proper divisors (2626859251340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2313204413140 is a wasteful number, since it uses less digits than its factorization.
2313204413140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1960342791 (or 1960342789 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 2313204413140 its reverse (413144023132), we get a palindrome (2726348436272).
The spelling of 2313204413140 in words is "two trillion, three hundred thirteen billion, two hundred four million, four hundred thirteen thousand, one hundred forty".
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