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3000133131120 = 243254166851571
BaseRepresentation
bin101011101010000101110…
…111101001101101110000
3101121210212102210001000100
4223222011313221231300
5343123233040143440
610214124144552400
7426516044565336
oct53520567515560
911553772701010
103000133131120
11a57392a370a4
12405542622700
13189bb02a3908
14a52c886db56
1553091290230
hex2ba85de9b70

3000133131120 has 60 divisors (see below), whose sum is σ = 10075447101096. Its totient is φ = 800035501440.

The previous prime is 3000133131019. The next prime is 3000133131179. The reversal of 3000133131120 is 211313310003.

It is a happy number.

3000133131120 is a `hidden beast` number, since 3 + 0 + 0 + 0 + 1 + 331 + 311 + 20 = 666.

It is a tau number, because it is divible by the number of its divisors (60).

It is a super-2 number, since 2×30001331311202 (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 3000133131093 and 3000133131102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2083425066 + ... + 2083426505.

Almost surely, 23000133131120 is an apocalyptic number.

3000133131120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

3000133131120 is an abundant number, since it is smaller than the sum of its proper divisors (7075313969976).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3000133131120 is a wasteful number, since it uses less digits than its factorization.

3000133131120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4166851590 (or 4166851581 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 3000133131120 its reverse (211313310003), we get a palindrome (3211446441123).

It can be divided in two parts, 3000133 and 131120, that added together give a triangular number (3131253 = T2502).

The spelling of 3000133131120 in words is "three trillion, one hundred thirty-three million, one hundred thirty-one thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 30 36 40 45 48 60 72 80 90 120 144 180 240 360 720 4166851571 8333703142 12500554713 16667406284 20834257855 25001109426 33334812568 37501664139 41668515710 50002218852 62502773565 66669625136 75003328278 83337031420 100004437704 125005547130 150006656556 166674062840 187508320695 200008875408 250011094260 300013313112 333348125680 375016641390 500022188520 600026626224 750033282780 1000044377040 1500066565560 3000133131120