Search a number
-
+
311021213100 = 2235213709112481
BaseRepresentation
bin1001000011010100100…
…11110001010110101100
31002201210121021122212220
410201222103301112230
520043432412304400
6354514155555340
731320252456063
oct4415223612654
91081717248786
10311021213100
1110a9a3403884
125034045bb50
1323438272890
14110a6b751da
15815503d7a0
hex486a4f15ac

311021213100 has 144 divisors (see below), whose sum is σ = 970485697440. Its totient is φ = 76450406400.

The previous prime is 311021212987. The next prime is 311021213117. The reversal of 311021213100 is 1312120113.

It is a happy number.

It is a super-2 number, since 2×3110212131002 (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 311021213100.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2708860 + ... + 2821340.

It is an arithmetic number, because the mean of its divisors is an integer number (6739484010).

Almost surely, 2311021213100 is an apocalyptic number.

311021213100 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 311021213100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (485242848720).

311021213100 is an abundant number, since it is smaller than the sum of its proper divisors (659464484340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311021213100 is a wasteful number, since it uses less digits than its factorization.

311021213100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113220 (or 113213 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 311021213100 its reverse (1312120113), we get a palindrome (312333333213).

The spelling of 311021213100 in words is "three hundred eleven billion, twenty-one million, two hundred thirteen thousand, one hundred".

Divisors: 1 2 3 4 5 6 10 12 13 15 20 25 26 30 39 50 52 60 65 75 78 100 130 150 156 195 260 300 325 390 650 709 780 975 1300 1418 1950 2127 2836 3545 3900 4254 7090 8508 9217 10635 14180 17725 18434 21270 27651 35450 36868 42540 46085 53175 55302 70900 92170 106350 110604 112481 138255 184340 212700 224962 230425 276510 337443 449924 460850 553020 562405 674886 691275 921700 1124810 1349772 1382550 1462253 1687215 2249620 2765100 2812025 2924506 3374430 4386759 5624050 5849012 6748860 7311265 8436075 8773518 11248100 14622530 16872150 17547036 21933795 29245060 33744300 36556325 43867590 73112650 79749029 87735180 109668975 146225300 159498058 219337950 239247087 318996116 398745145 438675900 478494174 797490290 956988348 1036737377 1196235435 1594980580 1993725725 2073474754 2392470870 3110212131 3987451450 4146949508 4784941740 5183686885 5981177175 6220424262 7974902900 10367373770 11962354350 12440848524 15551060655 20734747540 23924708700 25918434425 31102121310 51836868850 62204242620 77755303275 103673737700 155510606550 311021213100