31113111300120 has 128 divisors (see below), whose sum is σ = 105410541240000. Its totient is φ = 8160816061440.

The previous prime is 31113111300119. The next prime is 31113111300137. The reversal of 31113111300120 is 2100311131113.

31113111300120 is a `hidden beast` number, since 31 + 1 + 1 + 311 + 1 + 300 + 1 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 31113111300093 and 31113111300102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 236068845 + ... + 236200604.

Almost surely, 2^{31113111300120} is an apocalyptic number.

31113111300120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

31113111300120 is an abundant number, since it is smaller than the sum of its proper divisors (74297429939880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31113111300120 is a wasteful number, since it uses less digits than its factorization.

31113111300120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 472269530 (or 472269520 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 31113111300120 its reverse (2100311131113), we get a palindrome (33213422431233).

The spelling of 31113111300120 in words is "thirty-one trillion, one hundred thirteen billion, one hundred eleven million, three hundred thousand, one hundred twenty".