Base | Representation |
---|---|
bin | 101101010010100100110… |
… | …110101011111001010100 |
3 | 102000112110002011020101210 |
4 | 231102210312223321110 |
5 | 401443013430340200 |
6 | 10341440412221420 |
7 | 440600146351350 |
oct | 55224466537124 |
9 | 12015402136353 |
10 | 3112322121300 |
11 | a9aa237769a7 |
12 | 42323246a870 |
13 | 19764c148a82 |
14 | aa8cc666460 |
15 | 55e5a62c650 |
hex | 2d4a4dabe54 |
3112322121300 has 144 divisors (see below), whose sum is σ = 10738864668672. Its totient is φ = 680457993600.
The previous prime is 3112322121287. The next prime is 3112322121353. The reversal of 3112322121300 is 31212232113.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 32170356 + ... + 32266955.
It is an arithmetic number, because the mean of its divisors is an integer number (74575449088).
Almost surely, 23112322121300 is an apocalyptic number.
3112322121300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
3112322121300 is an abundant number, since it is smaller than the sum of its proper divisors (7626542547372).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3112322121300 is a wasteful number, since it uses less digits than its factorization.
3112322121300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64437358 (or 64437351 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 3112322121300 its reverse (31212232113), we get a palindrome (3143534353413).
The spelling of 3112322121300 in words is "three trillion, one hundred twelve billion, three hundred twenty-two million, one hundred twenty-one thousand, three hundred".
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