Base | Representation |
---|---|
bin | 100011011001000101111101… |
… | …1101100101011010000100010 |
3 | 1111211021010210111022121202110 |
4 | 1012302023323230223100202 |
5 | 311301014030314411120 |
6 | 3022034440010100150 |
7 | 122400360423052125 |
oct | 10662137354532042 |
9 | 1454233714277673 |
10 | 311312042341410 |
11 | 90214772017000 |
12 | 2aaba43911a656 |
13 | 104927a44c5776 |
14 | 56c38245d03bc |
15 | 25ece19a0d2e0 |
hex | 11b22fbb2b422 |
311312042341410 has 64 divisors (see below), whose sum is σ = 821807657483904. Its totient is φ = 75469586012480.
The previous prime is 311312042341379. The next prime is 311312042341507. The reversal of 311312042341410 is 14143240213113.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3898182489 + ... + 3898262348.
It is an arithmetic number, because the mean of its divisors is an integer number (12840744648186).
Almost surely, 2311312042341410 is an apocalyptic number.
311312042341410 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
311312042341410 is an abundant number, since it is smaller than the sum of its proper divisors (510495615142494).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311312042341410 is a wasteful number, since it uses less digits than its factorization.
311312042341410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7796444880 (or 7796444858 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 311312042341410 its reverse (14143240213113), we get a palindrome (325455282554523).
The spelling of 311312042341410 in words is "three hundred eleven trillion, three hundred twelve billion, forty-two million, three hundred forty-one thousand, four hundred ten".
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