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313311313113312 = 2533263659511597
BaseRepresentation
bin100011100111101000111100…
…1100001011011000011100000
31112002100021021002222211211110
41013033101321201123003200
5312031243032124111222
63030205121421143320
7122664665262163563
oct10717217141330340
91462307232884743
10313311313113312
1190915644274a38
122b1819b89bab40
13105a918c955c07
1457524c42984da
152634e2d99330c
hex11cf47985b0e0

313311313113312 has 24 divisors (see below), whose sum is σ = 822442196922696. Its totient is φ = 104437104371072.

The previous prime is 313311313113187. The next prime is 313311313113317. The reversal of 313311313113312 is 213311313113313.

It is a tau number, because it is divible by the number of its divisors (24).

It is a nude number because it is divisible by every one of its digits.

It is a self number, because there is not a number n which added to its sum of digits gives 313311313113312.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (313311313113317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1631829755703 + ... + 1631829755894.

It is an arithmetic number, because the mean of its divisors is an integer number (34268424871779).

Almost surely, 2313311313113312 is an apocalyptic number.

313311313113312 is a gapful number since it is divisible by the number (32) formed by its first and last digit.

It is an amenable number.

313311313113312 is an abundant number, since it is smaller than the sum of its proper divisors (509130883809384).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

313311313113312 is a wasteful number, since it uses less digits than its factorization.

313311313113312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3263659511610 (or 3263659511602 counting only the distinct ones).

The product of its digits is 4374, while the sum is 30.

Adding to 313311313113312 its reverse (213311313113313), we get a palindrome (526622626226625).

Subtracting from 313311313113312 its reverse (213311313113313), we obtain a palindrome (99999999999999).

It can be divided in two parts, 31331131 and 3113312, that added together give a palindrome (34444443).

The spelling of 313311313113312 in words is "three hundred thirteen trillion, three hundred eleven billion, three hundred thirteen million, one hundred thirteen thousand, three hundred twelve".

Divisors: 1 2 3 4 6 8 12 16 24 32 48 96 3263659511597 6527319023194 9790978534791 13054638046388 19581957069582 26109276092776 39163914139164 52218552185552 78327828278328 104437104371104 156655656556656 313311313113312