Base | Representation |
---|---|
bin | 1001001001101100111… |
… | …11110001110010000000 |
3 | 1010001122100100020012122 |
4 | 10210312133301302000 |
5 | 20122441402201030 |
6 | 400242132343412 |
7 | 31501200441230 |
oct | 4446637616200 |
9 | 1101570306178 |
10 | 314446912640 |
11 | 1113a10a2623 |
12 | 50b37774b68 |
13 | 23862bc6123 |
14 | 1130db11cc0 |
15 | 82a5b708e5 |
hex | 49367f1c80 |
314446912640 has 64 divisors (see below), whose sum is σ = 859113898560. Its totient is φ = 107810368512.
The previous prime is 314446912639. The next prime is 314446912711. The reversal of 314446912640 is 46219644413.
It is a tau number, because it is divible by the number of its divisors (64).
It is a super-3 number, since 3×3144469126403 (a number of 35 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 314446912591 and 314446912600.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35090042 + ... + 35099001.
It is an arithmetic number, because the mean of its divisors is an integer number (13423654665).
Almost surely, 2314446912640 is an apocalyptic number.
It is an amenable number.
314446912640 is an abundant number, since it is smaller than the sum of its proper divisors (544666985920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
314446912640 is an equidigital number, since it uses as much as digits as its factorization.
314446912640 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70189069 (or 70189057 counting only the distinct ones).
The product of its (nonzero) digits is 497664, while the sum is 44.
The spelling of 314446912640 in words is "three hundred fourteen billion, four hundred forty-six million, nine hundred twelve thousand, six hundred forty".
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