Base | Representation |
---|---|
bin | 111010110100100010010… |
… | …100111100011011110100 |
3 | 112022102110200210200101020 |
4 | 322310202110330123310 |
5 | 1012211300334010200 |
6 | 12332533351301140 |
7 | 565015000204662 |
oct | 72644224743364 |
9 | 15272420720336 |
10 | 4042140141300 |
11 | 1319297805528 |
12 | 55348867a7b0 |
13 | 234231381aa1 |
14 | dd8d7c45c32 |
15 | 7022a7d7ea0 |
hex | 3ad2253c6f4 |
4042140141300 has 72 divisors (see below), whose sum is σ = 11967241610016. Its totient is φ = 1052836498560.
The previous prime is 4042140141283. The next prime is 4042140141311. The reversal of 4042140141300 is 31410412404.
It is a super-3 number, since 3×40421401413003 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 156659199 + ... + 156684998.
It is an arithmetic number, because the mean of its divisors is an integer number (166211689028).
Almost surely, 24042140141300 is an apocalyptic number.
It is an amenable number.
4042140141300 is an abundant number, since it is smaller than the sum of its proper divisors (7925101468716).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4042140141300 is a wasteful number, since it uses less digits than its factorization.
4042140141300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 313344257 (or 313344250 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 4042140141300 its reverse (31410412404), we get a palindrome (4073550553704).
The spelling of 4042140141300 in words is "four trillion, forty-two billion, one hundred forty million, one hundred forty-one thousand, three hundred".
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