Base | Representation |
---|---|
bin | 111010110100101110001… |
… | …111110011101011010100 |
3 | 112022102222122002201100220 |
4 | 322310232033303223110 |
5 | 1012212203032340200 |
6 | 12333005253434340 |
7 | 565022646050025 |
oct | 72645617635324 |
9 | 15272878081326 |
10 | 4042340121300 |
11 | 131938a684458 |
12 | 55352363b9b0 |
13 | 23426392cc50 |
14 | dd916620c4c |
15 | 7023d13b4a0 |
hex | 3ad2e3f3ad4 |
4042340121300 has 72 divisors (see below), whose sum is σ = 12595517231136. Its totient is φ = 995037567360.
The previous prime is 4042340121277. The next prime is 4042340121311. The reversal of 4042340121300 is 31210432404.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 518244834 + ... + 518252633.
Almost surely, 24042340121300 is an apocalyptic number.
It is an amenable number.
4042340121300 is an abundant number, since it is smaller than the sum of its proper divisors (8553177109836).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4042340121300 is a wasteful number, since it uses less digits than its factorization.
4042340121300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1036497497 (or 1036497490 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 4042340121300 its reverse (31210432404), we get a palindrome (4073550553704).
The spelling of 4042340121300 in words is "four trillion, forty-two billion, three hundred forty million, one hundred twenty-one thousand, three hundred".
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