Base | Representation |
---|---|
bin | 1011111111011011110… |
… | …10100000111001010000 |
3 | 1110101110220221222010120 |
4 | 11333231322200321100 |
5 | 23222300414314100 |
6 | 513135405430240 |
7 | 41524035251163 |
oct | 5775572407120 |
9 | 1411426858116 |
10 | 412013432400 |
11 | 149808928a29 |
12 | 67a2656b380 |
13 | 2cb114c6b1b |
14 | 15d278b9ada |
15 | aab641e0a0 |
hex | 5fedea0e50 |
412013432400 has 120 divisors (see below), whose sum is σ = 1320126161280. Its totient is φ = 109844459520.
The previous prime is 412013432393. The next prime is 412013432449. The reversal of 412013432400 is 4234310214.
It is a tau number, because it is divible by the number of its divisors (120).
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5377561 + ... + 5453639.
It is an arithmetic number, because the mean of its divisors is an integer number (11001051344).
Almost surely, 2412013432400 is an apocalyptic number.
412013432400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
412013432400 is an abundant number, since it is smaller than the sum of its proper divisors (908112728880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
412013432400 is a wasteful number, since it uses less digits than its factorization.
412013432400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80613 (or 80602 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 412013432400 its reverse (4234310214), we get a palindrome (416247742614).
The spelling of 412013432400 in words is "four hundred twelve billion, thirteen million, four hundred thirty-two thousand, four hundred".
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