Base | Representation |
---|---|
bin | 1100101000100110011… |
… | …01111010101100101100 |
3 | 1112111112011021211110120 |
4 | 12110103031322230230 |
5 | 24103031203043200 |
6 | 531232420004540 |
7 | 43235516033241 |
oct | 6242315725454 |
9 | 1474464254416 |
10 | 434114112300 |
11 | 15811a10a940 |
12 | 70173b30750 |
13 | 31c24169bcb |
14 | 17022b875c8 |
15 | b45b7d89a0 |
hex | 651337ab2c |
434114112300 has 72 divisors (see below), whose sum is σ = 1370222008512. Its totient is φ = 105239784000.
The previous prime is 434114112269. The next prime is 434114112323. The reversal of 434114112300 is 3211411434.
434114112300 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×4341141123002 (a number of 24 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 65771566 + ... + 65778165.
Almost surely, 2434114112300 is an apocalyptic number.
It is an amenable number.
434114112300 is an abundant number, since it is smaller than the sum of its proper divisors (936107896212).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
434114112300 is a wasteful number, since it uses less digits than its factorization.
434114112300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131549759 (or 131549752 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 434114112300 its reverse (3211411434), we get a palindrome (437325523734).
It can be divided in two parts, 4341 and 14112300, that added together give a triangular number (14116641 = T5313).
The spelling of 434114112300 in words is "four hundred thirty-four billion, one hundred fourteen million, one hundred twelve thousand, three hundred".
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