Base | Representation |
---|---|
bin | 100101000110111111011… |
… | …0110101011101100110100 |
3 | 200001120122111112120200100 |
4 | 1022031332312223230310 |
5 | 1132030310114204330 |
6 | 14503005145114100 |
7 | 1034324026322646 |
oct | 112157666535464 |
9 | 20046574476610 |
10 | 5100254444340 |
11 | 1697007741440 |
12 | 6a4568a88930 |
13 | 2acc4b511293 |
14 | 138bd451c896 |
15 | 8ca08e6c060 |
hex | 4a37edabb34 |
5100254444340 has 144 divisors (see below), whose sum is σ = 16877950217856. Its totient is φ = 1236370771200.
The previous prime is 5100254444333. The next prime is 5100254444357. The reversal of 5100254444340 is 434444520015.
5100254444340 is a `hidden beast` number, since 5 + 100 + 2 + 544 + 4 + 4 + 3 + 4 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a junction number, because it is equal to n+sod(n) for n = 5100254444295 and 5100254444304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 61875394 + ... + 61957766.
It is an arithmetic number, because the mean of its divisors is an integer number (117207987624).
Almost surely, 25100254444340 is an apocalyptic number.
It is an amenable number.
5100254444340 is an abundant number, since it is smaller than the sum of its proper divisors (11777695773516).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5100254444340 is a wasteful number, since it uses less digits than its factorization.
5100254444340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 113670 (or 113665 counting only the distinct ones).
The product of its (nonzero) digits is 153600, while the sum is 36.
Adding to 5100254444340 its reverse (434444520015), we get a palindrome (5534698964355).
The spelling of 5100254444340 in words is "five trillion, one hundred billion, two hundred fifty-four million, four hundred forty-four thousand, three hundred forty".
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