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51213104000 = 275311932683
BaseRepresentation
bin101111101100100010…
…011111001110000000
311220012010111020110122
4233230202133032000
51314341023312000
635305454315412
73462052126052
oct575442371600
9156163436418
1051213104000
111a7a050a043
129b131b8b68
134aa21a1846
14269b8b18d2
1514eb11d085
hexbec89f380

51213104000 has 128 divisors (see below), whose sum is σ = 127482806880. Its totient is φ = 20460441600.

The previous prime is 51213103999. The next prime is 51213104009. The reversal of 51213104000 is 40131215.

51213104000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (128).

It is a self number, because there is not a number n which added to its sum of digits gives 51213104000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51213104009) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19086659 + ... + 19089341.

Almost surely, 251213104000 is an apocalyptic number.

51213104000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 51213104000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (63741403440).

51213104000 is an abundant number, since it is smaller than the sum of its proper divisors (76269702880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51213104000 is a wasteful number, since it uses less digits than its factorization.

51213104000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3905 (or 3883 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 17.

Adding to 51213104000 its reverse (40131215), we get a palindrome (51253235215).

The spelling of 51213104000 in words is "fifty-one billion, two hundred thirteen million, one hundred four thousand".

Divisors: 1 2 4 5 8 10 16 20 25 32 40 50 64 80 100 125 128 160 200 250 320 400 500 640 800 1000 1193 1600 2000 2386 2683 3200 4000 4772 5366 5965 8000 9544 10732 11930 13415 16000 19088 21464 23860 26830 29825 38176 42928 47720 53660 59650 67075 76352 85856 95440 107320 119300 134150 149125 152704 171712 190880 214640 238600 268300 298250 335375 343424 381760 429280 477200 536600 596500 670750 763520 858560 954400 1073200 1193000 1341500 1717120 1908800 2146400 2386000 2683000 3200819 3817600 4292800 4772000 5366000 6401638 8585600 9544000 10732000 12803276 16004095 19088000 21464000 25606552 32008190 42928000 51213104 64016380 80020475 102426208 128032760 160040950 204852416 256065520 320081900 400102375 409704832 512131040 640163800 800204750 1024262080 1280327600 1600409500 2048524160 2560655200 3200819000 5121310400 6401638000 10242620800 12803276000 25606552000 51213104000