Base | Representation |
---|---|
bin | 1100011010111… |
… | …0110001010000 |
3 | 10122000202101110 |
4 | 3012232301100 |
5 | 101314033310 |
6 | 5100333320 |
7 | 1201544421 |
oct | 306566120 |
9 | 118022343 |
10 | 52096080 |
11 | 27452613 |
12 | 15544240 |
13 | aa404aa |
14 | 6cc1648 |
15 | 4890d20 |
hex | 31aec50 |
52096080 has 80 divisors (see below), whose sum is σ = 162828864. Its totient is φ = 13777920.
The previous prime is 52096073. The next prime is 52096087. The reversal of 52096080 is 8069025.
52096080 is nontrivially palindromic in base 13.
It is an interprime number because it is at equal distance from previous prime (52096073) and next prime (52096087).
It is a tau number, because it is divible by the number of its divisors (80).
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52096087) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30612 + ... + 32268.
Almost surely, 252096080 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 52096080, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (81414432).
52096080 is an abundant number, since it is smaller than the sum of its proper divisors (110732784).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
52096080 is a wasteful number, since it uses less digits than its factorization.
52096080 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1804 (or 1798 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 30.
The square root of 52096080 is about 7217.7614258162. The cubic root of 52096080 is about 373.4808586468.
The spelling of 52096080 in words is "fifty-two million, ninety-six thousand, eighty".
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