Base | Representation |
---|---|
bin | 111100010000010101011001… |
… | …0100100100111001111010110 |
3 | 2120111121111212112100021010212 |
4 | 1320200222302210213033112 |
5 | 1023432143101323001400 |
6 | 5115123252504245422 |
7 | 216431666343655346 |
oct | 17040526244471726 |
9 | 2514544775307125 |
10 | 530010550203350 |
11 | 143972237274847 |
12 | 4b53b718a70872 |
13 | 19997a1b7a22c8 |
14 | 94c490ca6cd26 |
15 | 4141bcda18335 |
hex | 1e20ab29273d6 |
530010550203350 has 12 divisors (see below), whose sum is σ = 985819623378324. Its totient is φ = 212004220081320.
The previous prime is 530010550203319. The next prime is 530010550203353. The reversal of 530010550203350 is 53302055010035.
It is a super-2 number, since 2×5300105502033502 (a number of 30 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530010550203353) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5300105501984 + ... + 5300105502083.
It is an arithmetic number, because the mean of its divisors is an integer number (82151635281527).
Almost surely, 2530010550203350 is an apocalyptic number.
530010550203350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
530010550203350 is a deficient number, since it is larger than the sum of its proper divisors (455809073174974).
530010550203350 is a wasteful number, since it uses less digits than its factorization.
530010550203350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10600211004079 (or 10600211004074 counting only the distinct ones).
The product of its (nonzero) digits is 33750, while the sum is 32.
The spelling of 530010550203350 in words is "five hundred thirty trillion, ten billion, five hundred fifty million, two hundred three thousand, three hundred fifty".
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