Base | Representation |
---|---|
bin | 111100010001000000100101… |
… | …1000100111000011101100110 |
3 | 2120111221101021122022020202012 |
4 | 1320202001023010320131212 |
5 | 1023440203031044100200 |
6 | 5115234032345114222 |
7 | 216441462011460266 |
oct | 17042011304703546 |
9 | 2514841248266665 |
10 | 530103303112550 |
11 | 1439a860392a302 |
12 | 4b5556a3788972 |
13 | 199a36b0a4462b |
14 | 94c91cb4137a6 |
15 | 414430b8cba35 |
hex | 1e2204b138766 |
530103303112550 has 12 divisors (see below), whose sum is σ = 985992143789436. Its totient is φ = 212041321245000.
The previous prime is 530103303112501. The next prime is 530103303112553. The reversal of 530103303112550 is 55211303301035.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530103303112553) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5301033031076 + ... + 5301033031175.
It is an arithmetic number, because the mean of its divisors is an integer number (82166011982453).
Almost surely, 2530103303112550 is an apocalyptic number.
530103303112550 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
530103303112550 is a deficient number, since it is larger than the sum of its proper divisors (455888840676886).
530103303112550 is a wasteful number, since it uses less digits than its factorization.
530103303112550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10602066062263 (or 10602066062258 counting only the distinct ones).
The product of its (nonzero) digits is 20250, while the sum is 32.
Adding to 530103303112550 its reverse (55211303301035), we get a palindrome (585314606413585).
The spelling of 530103303112550 in words is "five hundred thirty trillion, one hundred three billion, three hundred three million, one hundred twelve thousand, five hundred fifty".
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