Base | Representation |
---|---|
bin | 110001011001101000… |
… | …010100111011001000 |
3 | 12001220200102102200110 |
4 | 301121220110323020 |
5 | 1332113044214430 |
6 | 40211235034320 |
7 | 3555315021615 |
oct | 613150247310 |
9 | 161820372613 |
10 | 53043351240 |
11 | 2054a652970 |
12 | a34413b9a0 |
13 | 5004422289 |
14 | 27d29bd50c |
15 | 15a6b4d7b0 |
hex | c59a14ec8 |
53043351240 has 64 divisors (see below), whose sum is σ = 173596426560. Its totient is φ = 12858993920.
The previous prime is 53043351239. The next prime is 53043351253. The reversal of 53043351240 is 4215334035.
It is a super-2 number, since 2×530433512402 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 53043351198 and 53043351207.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20090859 + ... + 20093498.
It is an arithmetic number, because the mean of its divisors is an integer number (2712444165).
Almost surely, 253043351240 is an apocalyptic number.
It is an amenable number.
53043351240 is an abundant number, since it is smaller than the sum of its proper divisors (120553075320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53043351240 is a wasteful number, since it uses less digits than its factorization.
53043351240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40184382 (or 40184378 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 30.
Adding to 53043351240 its reverse (4215334035), we get a palindrome (57258685275).
The spelling of 53043351240 in words is "fifty-three billion, forty-three million, three hundred fifty-one thousand, two hundred forty".
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