Base | Representation |
---|---|
bin | 111100011000100000010100… |
… | …1101100001001011011010110 |
3 | 2120122120212111021121100120020 |
4 | 1320301000221230021123112 |
5 | 1024104042434443200400 |
6 | 5121343213320450010 |
7 | 216606063064236654 |
oct | 17061005154113326 |
9 | 2518525437540506 |
10 | 531133535131350 |
11 | 144265515a603a8 |
12 | 4b6a12a2319906 |
13 | 19a498a6490398 |
14 | 9523000a1ddd4 |
15 | 41610072ed2a0 |
hex | 1e31029b096d6 |
531133535131350 has 96 divisors (see below), whose sum is σ = 1335033005169024. Its totient is φ = 139724279692800.
The previous prime is 531133535131337. The next prime is 531133535131387. The reversal of 531133535131350 is 53131535331135.
It is a super-2 number, since 2×5311335351313502 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 22727491 + ... + 39734190.
It is an arithmetic number, because the mean of its divisors is an integer number (13906593803844).
Almost surely, 2531133535131350 is an apocalyptic number.
531133535131350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
531133535131350 is an abundant number, since it is smaller than the sum of its proper divisors (803899470037674).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
531133535131350 is a wasteful number, since it uses less digits than its factorization.
531133535131350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62462462 (or 62462457 counting only the distinct ones).
The product of its (nonzero) digits is 455625, while the sum is 42.
The spelling of 531133535131350 in words is "five hundred thirty-one trillion, one hundred thirty-three billion, five hundred thirty-five million, one hundred thirty-one thousand, three hundred fifty".
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