Base | Representation |
---|---|
bin | 100110101010001010010… |
… | …1111000111010010100100 |
3 | 200210221100121101201002000 |
4 | 1031110110233013102210 |
5 | 1144022434421040400 |
6 | 15144505524245300 |
7 | 1055603414400531 |
oct | 115242457072244 |
9 | 20727317351060 |
10 | 5313222440100 |
11 | 1769363608803 |
12 | 7198a3540830 |
13 | 2c705b3a7b13 |
14 | 1452389d7d88 |
15 | 93320b20600 |
hex | 4d514bc74a4 |
5313222440100 has 144 divisors (see below), whose sum is σ = 17670027379200. Its totient is φ = 1368002079360.
The previous prime is 5313222440087. The next prime is 5313222440101. The reversal of 5313222440100 is 10442223135.
5313222440100 is a `hidden beast` number, since 5 + 3 + 1 + 32 + 224 + 401 + 0 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (5313222440101) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 33850324 + ... + 34006923.
Almost surely, 25313222440100 is an apocalyptic number.
5313222440100 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5313222440100 is an abundant number, since it is smaller than the sum of its proper divisors (12356804939100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5313222440100 is a wasteful number, since it uses less digits than its factorization.
5313222440100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67857299 (or 67857286 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 5313222440100 its reverse (10442223135), we get a palindrome (5323664663235).
The spelling of 5313222440100 in words is "five trillion, three hundred thirteen billion, two hundred twenty-two million, four hundred forty thousand, one hundred".
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