Base | Representation |
---|---|
bin | 11101011011100001110… |
… | …00101001000111000000 |
3 | 10120200010001021222000111 |
4 | 32231300320221013000 |
5 | 113031430032224300 |
6 | 2052313301401104 |
7 | 133025520321661 |
oct | 16556070510700 |
9 | 3520101258014 |
10 | 1011211211200 |
11 | 35a9414038a3 |
12 | 143b90709194 |
13 | 74483ba4418 |
14 | 36d2b3b7368 |
15 | 1b485b269ba |
hex | eb70e291c0 |
1011211211200 has 84 divisors (see below), whose sum is σ = 2506112940520. Its totient is φ = 401574435840.
The previous prime is 1011211211141. The next prime is 1011211211201. The reversal of 1011211211200 is 21121121101.
It is a happy number.
It is a super-2 number, since 2×10112112112002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1011211211201) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2051007 + ... + 2495806.
Almost surely, 21011211211200 is an apocalyptic number.
1011211211200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1011211211200 is an abundant number, since it is smaller than the sum of its proper divisors (1494901729320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1011211211200 is a wasteful number, since it uses less digits than its factorization.
1011211211200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4546974 (or 4546959 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 1011211211200 its reverse (21121121101), we get a palindrome (1032332332301).
Subtracting from 1011211211200 its reverse (21121121101), we obtain a palindrome (990090090099).
The spelling of 1011211211200 in words is "one trillion, eleven billion, two hundred eleven million, two hundred eleven thousand, two hundred".
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