101140401312 has 144 divisors (see below), whose sum is σ = 290780741160. Its totient is φ = 33343488000.

The previous prime is 101140401311. The next prime is 101140401359. The reversal of 101140401312 is 213104041101.

It can be written as a sum of positive squares in 4 ways, for example, as 93291150096 + 7849251216 = 305436^2 + 88596^2 .

It is a tau number, because it is divible by the number of its divisors (144).

It is a super-2 number, since 2×101140401312² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (101140401311) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 46801512 + ... + 46803672.

Almost surely, 2^101140401312 is an apocalyptic number.

101140401312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101140401312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (145390370580).

101140401312 is an abundant number, since it is smaller than the sum of its proper divisors (189640339848).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101140401312 is a wasteful number, since it uses less digits than its factorization.

101140401312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3887 (or 3876 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 101140401312 its reverse (213104041101), we get a palindrome (314244442413).

The spelling of 101140401312 in words is "one hundred one billion, one hundred forty million, four hundred one thousand, three hundred twelve".