Base | Representation |
---|---|
bin | 110000000001100000… |
… | …1110011110100000000 |
3 | 100212012022022220000212 |
4 | 1200003001303310000 |
5 | 3142202241133440 |
6 | 115213254133252 |
7 | 10310441500340 |
oct | 1400301636400 |
9 | 325168286025 |
10 | 103130021120 |
11 | 3a812232315 |
12 | 17ba2051228 |
13 | 9957119249 |
14 | 4dc4a30d20 |
15 | 2a38e13465 |
hex | 1803073d00 |
103130021120 has 72 divisors (see below), whose sum is σ = 282318457344. Its totient is φ = 35358861312.
The previous prime is 103130021119. The next prime is 103130021171. The reversal of 103130021120 is 21120031301.
It is a Harshad number since it is a multiple of its sum of digits (14).
It is a junction number, because it is equal to n+sod(n) for n = 103130021095 and 103130021104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5746064 + ... + 5763983.
Almost surely, 2103130021120 is an apocalyptic number.
103130021120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
103130021120 is an abundant number, since it is smaller than the sum of its proper divisors (179188436224).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103130021120 is an equidigital number, since it uses as much as digits as its factorization.
103130021120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11510075 (or 11510061 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 103130021120 its reverse (21120031301), we get a palindrome (124250052421).
The spelling of 103130021120 in words is "one hundred three billion, one hundred thirty million, twenty-one thousand, one hundred twenty".
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