Base | Representation |
---|---|
bin | 11110000000111110000… |
… | …10111000011110000000 |
3 | 10122120222222100122200122 |
4 | 33000133002320132000 |
5 | 113344112112002240 |
6 | 2105440104435412 |
7 | 134336616602111 |
oct | 17003702703600 |
9 | 3576888318618 |
10 | 1031313000320 |
11 | 368417336559 |
12 | 147a60778b68 |
13 | 7633869acb5 |
14 | 37cb6dd8208 |
15 | 1bc6079c4b5 |
hex | f01f0b8780 |
1031313000320 has 32 divisors (see below), whose sum is σ = 2465482642920. Its totient is φ = 412525199872.
The previous prime is 1031313000301. The next prime is 1031313000323. The reversal of 1031313000320 is 230003131301.
It is a tau number, because it is divible by the number of its divisors (32).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1031313000323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 805712642 + ... + 805713921.
Almost surely, 21031313000320 is an apocalyptic number.
1031313000320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1031313000320 is an abundant number, since it is smaller than the sum of its proper divisors (1434169642600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1031313000320 is an equidigital number, since it uses as much as digits as its factorization.
1031313000320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1611426582 (or 1611426570 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 1031313000320 its reverse (230003131301), we get a palindrome (1261316131621).
The spelling of 1031313000320 in words is "one trillion, thirty-one billion, three hundred thirteen million, three hundred twenty", and thus it is an aban number.
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