Base | Representation |
---|---|
bin | 10111011110001101011110… |
… | …110110011111001101110100 |
3 | 111112111210120222000122111110 |
4 | 113132031132312133031310 |
5 | 102012314323324120200 |
6 | 1003315420534435020 |
7 | 30513126433430301 |
oct | 2736153666371564 |
9 | 445453528018443 |
10 | 103231130301300 |
11 | 2a990092909191 |
12 | b6b2a74802a70 |
13 | 457a866589c31 |
14 | 1b6c5b03c00a8 |
15 | be042a430b50 |
hex | 5de35ed9f374 |
103231130301300 has 72 divisors (see below), whose sum is σ = 311668247330496. Its totient is φ = 26331418741760.
The previous prime is 103231130301287. The next prime is 103231130301337. The reversal of 103231130301300 is 3103031132301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7480509789 + ... + 7480523588.
It is an arithmetic number, because the mean of its divisors is an integer number (4328725657368).
Almost surely, 2103231130301300 is an apocalyptic number.
103231130301300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
103231130301300 is an abundant number, since it is smaller than the sum of its proper divisors (208437117029196).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103231130301300 is a wasteful number, since it uses less digits than its factorization.
103231130301300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14961033417 (or 14961033410 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 103231130301300 its reverse (3103031132301), we get a palindrome (106334161433601).
The spelling of 103231130301300 in words is "one hundred three trillion, two hundred thirty-one billion, one hundred thirty million, three hundred one thousand, three hundred".
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