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11001331113120 = 2532529263441837
BaseRepresentation
bin1010000000010111001001…
…1011101101110010100000
31102221201100200101020020100
42200011302123231302200
52420221211231104440
635221535225542400
72213551145356515
oct240056233556240
942851320336210
1011001331113120
1135617026779a7
12129816b644a00
1361a56213385a
142a067827530c
15141283493230
hexa01726edca0

11001331113120 has 144 divisors (see below), whose sum is σ = 38836595757960. Its totient is φ = 2832526620672.

The previous prime is 11001331113077. The next prime is 11001331113121. The reversal of 11001331113120 is 2131113310011.

11001331113120 is a `hidden beast` number, since 1 + 10 + 0 + 1 + 331 + 11 + 312 + 0 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 7937584986384 + 3063746126736 = 2817372^2 + 1750356^2 .

It is a tau number, because it is divible by the number of its divisors (144).

It is a super-2 number, since 2×110013311131202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 11001331113093 and 11001331113102.

It is not an unprimeable number, because it can be changed into a prime (11001331113121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 131679159 + ... + 131762678.

Almost surely, 211001331113120 is an apocalyptic number.

11001331113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11001331113120 is an abundant number, since it is smaller than the sum of its proper divisors (27835264644840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11001331113120 is a wasteful number, since it uses less digits than its factorization.

11001331113120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 263441887 (or 263441876 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 11001331113120 its reverse (2131113310011), we get a palindrome (13132444423131).

The spelling of 11001331113120 in words is "eleven trillion, one billion, three hundred thirty-one million, one hundred thirteen thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 29 30 32 36 40 45 48 58 60 72 80 87 90 96 116 120 144 145 160 174 180 232 240 261 288 290 348 360 435 464 480 522 580 696 720 870 928 1044 1160 1305 1392 1440 1740 2088 2320 2610 2784 3480 4176 4640 5220 6960 8352 10440 13920 20880 41760 263441837 526883674 790325511 1053767348 1317209185 1580651022 2107534696 2370976533 2634418370 3161302044 3951627555 4215069392 4741953066 5268836740 6322604088 7639813273 7903255110 8430138784 9483906132 10537673480 11854882665 12645208176 15279626546 15806510220 18967812264 21075346960 22919439819 23709765330 25290416352 30559253092 31613020440 37935624528 38199066365 42150693920 45838879638 47419530660 61118506184 63226040880 68758319457 75871249056 76398132730 91677759276 94839061320 114597199095 122237012368 126452081760 137516638914 152796265460 183355518552 189678122640 229194398190 244474024736 275033277828 305592530920 343791597285 366711037104 379356245280 458388796380 550066555656 611185061840 687583194570 733422074208 916777592760 1100133111312 1222370123680 1375166389140 1833555185520 2200266222624 2750332778280 3667110371040 5500665556560 11001331113120